2x-3y-6=0;2x-y+2=0

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for example:
2x+y=8
x+3y=14

Solution for 2x-3y-6=0;2x-y+2=0 system of equations: 


  • /| 2*x-(3*y)-6 = 0| 2*x-y+2 = 0
  • We try to solve the equation: 2*x-(3*y)-6 = 0
  • 2*x-3*y-6 = 0 // - 2*x-6
  • -3*y = -(2*x-6) // : -3
  • y = (-(2*x-6))/(-3)
  • y = (6-(2*x))/(-3)
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 2*x-((6-(2*x))/(-3))+2 = 0| y = (6-(2*x))/(-3)
  • (-1*(6-2*x))/(-3)+2*x+2 = 0
  • 4/3*x+2+2 = 0
  • 4/3*x+4 = 0
  • 4/3*x+4 = 0 // - 4
  • 4/3*x = -4 // : 4/3
  • x = -4/4/3
  • x = -3
  • We insert the solution into one of the initial equations of our system of equations
  • For y = (6-(2*x))/(-3): 
  • y = (6-(-3*2))/(-3)
  • y = (6+6)/(-3)
  • y = 12/(-3)
  • y = -4
  • We get a system of equations:
  • /| y = -4| x = -3

 

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