2x-3y=24;3x+3y=-39

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Solution for 2x-3y=24;3x+3y=-39 system of equations: 


  • /| 2*x-(3*y)-24 = 0| 3*x+3*y+39 = 0
  • We try to solve the equation: 2*x-(3*y)-24 = 0
  • 2*x-3*y-24 = 0 // - 2*x-24
  • -3*y = -(2*x-24) // : -3
  • y = (-(2*x-24))/(-3)
  • y = (24-(2*x))/(-3)
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 3*((24-(2*x))/(-3))+3*x+39 = 0| y = (24-(2*x))/(-3)
  • (3*(24-2*x))/(-3)+3*x+39 = 0
  • 5*x-24+39 = 0
  • 5*x+15 = 0
  • 5*x+15 = 0 // - 15
  • 5*x = -15 // : 5
  • x = -15/5
  • x = -3
  • We insert the solution into one of the initial equations of our system of equations
  • For y = (24-(2*x))/(-3): 
  • y = (24-(-3*2))/(-3)
  • y = (6+24)/(-3)
  • y = 30/(-3)
  • y = -10
  • We get a system of equations:
  • /| y = -10| x = -3

 

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