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2x-4(2x-3)=6(x+4)
We move all terms to the left:
2x-4(2x-3)-(6(x+4))=0
We multiply parentheses
2x-8x-(6(x+4))+12=0
We calculate terms in parentheses: -(6(x+4)), so:We add all the numbers together, and all the variables
6(x+4)
We multiply parentheses
6x+24
Back to the equation:
-(6x+24)
-6x-(6x+24)+12=0
We get rid of parentheses
-6x-6x-24+12=0
We add all the numbers together, and all the variables
-12x-12=0
We move all terms containing x to the left, all other terms to the right
-12x=12
x=12/-12
x=-1
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