2x-4(3-2x)=4(x-4)-8

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Solution for 2x-4(3-2x)=4(x-4)-8 equation: 



2x-4(3-2x)=4(x-4)-8

We move all terms to the left:

2x-4(3-2x)-(4(x-4)-8)=0

We add all the numbers together, and all the variables

2x-4(-2x+3)-(4(x-4)-8)=0

We multiply parentheses

2x+8x-(4(x-4)-8)-12=0



We calculate terms in parentheses: -(4(x-4)-8), so:

4(x-4)-8

We multiply parentheses

4x-16-8

We add all the numbers together, and all the variables

4x-24

Back to the equation:

-(4x-24)



We add all the numbers together, and all the variables

10x-(4x-24)-12=0

We get rid of parentheses

10x-4x+24-12=0

We add all the numbers together, and all the variables

6x+12=0

We move all terms containing x to the left, all other terms to the right

6x=-12

x=-12/6

x=-2

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