2x-4(3x+19)=16

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Solution for 2x-4(3x+19)=16 equation: 



2x-4(3x+19)=16

We move all terms to the left:

2x-4(3x+19)-(16)=0

We multiply parentheses

2x-12x-76-16=0

We add all the numbers together, and all the variables

-10x-92=0

We move all terms containing x to the left, all other terms to the right

-10x=92

x=92/-10

x=-9+1/5

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