2x-4(3x+19)=16

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Solution for 2x-4(3x+19)=16 equation:



2x-4(3x+19)=16
We move all terms to the left:
2x-4(3x+19)-(16)=0
We multiply parentheses
2x-12x-76-16=0
We add all the numbers together, and all the variables
-10x-92=0
We move all terms containing x to the left, all other terms to the right
-10x=92
x=92/-10
x=-9+1/5

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