2x-4(3x-10)=-10x+40

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Solution for 2x-4(3x-10)=-10x+40 equation: 



2x-4(3x-10)=-10x+40

We move all terms to the left:

2x-4(3x-10)-(-10x+40)=0

We multiply parentheses

2x-12x-(-10x+40)+40=0

We get rid of parentheses

2x-12x+10x-40+40=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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