2x-4(3x-2)-8(2x+1)=

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Solution for 2x-4(3x-2)-8(2x+1)= equation:


Simplifying
2x + -4(3x + -2) + -8(2x + 1) = 0

Reorder the terms:
2x + -4(-2 + 3x) + -8(2x + 1) = 0
2x + (-2 * -4 + 3x * -4) + -8(2x + 1) = 0
2x + (8 + -12x) + -8(2x + 1) = 0

Reorder the terms:
2x + 8 + -12x + -8(1 + 2x) = 0
2x + 8 + -12x + (1 * -8 + 2x * -8) = 0
2x + 8 + -12x + (-8 + -16x) = 0

Reorder the terms:
8 + -8 + 2x + -12x + -16x = 0

Combine like terms: 8 + -8 = 0
0 + 2x + -12x + -16x = 0
2x + -12x + -16x = 0

Combine like terms: 2x + -12x = -10x
-10x + -16x = 0

Combine like terms: -10x + -16x = -26x
-26x = 0

Solving
-26x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '-26'.
x = 0

Simplifying
x = 0

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