2x-4(4x+4)=128

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Solution for 2x-4(4x+4)=128 equation: 



2x-4(4x+4)=128

We move all terms to the left:

2x-4(4x+4)-(128)=0

We multiply parentheses

2x-16x-16-128=0

We add all the numbers together, and all the variables

-14x-144=0

We move all terms containing x to the left, all other terms to the right

-14x=144

x=144/-14

x=-10+2/7

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