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2x-4(x+1)=2(5-x)
We move all terms to the left:
2x-4(x+1)-(2(5-x))=0
We add all the numbers together, and all the variables
2x-4(x+1)-(2(-1x+5))=0
We multiply parentheses
2x-4x-(2(-1x+5))-4=0
We calculate terms in parentheses: -(2(-1x+5)), so:We add all the numbers together, and all the variables
2(-1x+5)
We multiply parentheses
-2x+10
Back to the equation:
-(-2x+10)
-2x-(-2x+10)-4=0
We get rid of parentheses
-2x+2x-10-4=0
We add all the numbers together, and all the variables
-14!=0
There is no solution for this equation
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