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2x-4(x+12)=2(4x+3)
We move all terms to the left:
2x-4(x+12)-(2(4x+3))=0
We multiply parentheses
2x-4x-(2(4x+3))-48=0
We calculate terms in parentheses: -(2(4x+3)), so:We add all the numbers together, and all the variables
2(4x+3)
We multiply parentheses
8x+6
Back to the equation:
-(8x+6)
-2x-(8x+6)-48=0
We get rid of parentheses
-2x-8x-6-48=0
We add all the numbers together, and all the variables
-10x-54=0
We move all terms containing x to the left, all other terms to the right
-10x=54
x=54/-10
x=-5+2/5
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