2x-4(x-2)=-7+4x-33

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Solution for 2x-4(x-2)=-7+4x-33 equation: 



2x-4(x-2)=-7+4x-33

We move all terms to the left:

2x-4(x-2)-(-7+4x-33)=0

We add all the numbers together, and all the variables

2x-4(x-2)-(4x-40)=0

We multiply parentheses

2x-4x-(4x-40)+8=0

We get rid of parentheses

2x-4x-4x+40+8=0

We add all the numbers together, and all the variables

-6x+48=0

We move all terms containing x to the left, all other terms to the right

-6x=-48

x=-48/-6

x=+8

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