2x-4(x-2)=-8+3x+6

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Solution for 2x-4(x-2)=-8+3x+6 equation: 



2x-4(x-2)=-8+3x+6

We move all terms to the left:

2x-4(x-2)-(-8+3x+6)=0

We add all the numbers together, and all the variables

2x-4(x-2)-(3x-2)=0

We multiply parentheses

2x-4x-(3x-2)+8=0

We get rid of parentheses

2x-4x-3x+2+8=0

We add all the numbers together, and all the variables

-5x+10=0

We move all terms containing x to the left, all other terms to the right

-5x=-10

x=-10/-5

x=+2

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