2x-4(x-3)=-4+3x-19

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Solution for 2x-4(x-3)=-4+3x-19 equation: 



2x-4(x-3)=-4+3x-19

We move all terms to the left:

2x-4(x-3)-(-4+3x-19)=0

We add all the numbers together, and all the variables

2x-4(x-3)-(3x-23)=0

We multiply parentheses

2x-4x-(3x-23)+12=0

We get rid of parentheses

2x-4x-3x+23+12=0

We add all the numbers together, and all the variables

-5x+35=0

We move all terms containing x to the left, all other terms to the right

-5x=-35

x=-35/-5

x=+7

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