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2x-4(x-3)=-5+3x-23
We move all terms to the left:
2x-4(x-3)-(-5+3x-23)=0
We add all the numbers together, and all the variables
2x-4(x-3)-(3x-28)=0
We multiply parentheses
2x-4x-(3x-28)+12=0
We get rid of parentheses
2x-4x-3x+28+12=0
We add all the numbers together, and all the variables
-5x+40=0
We move all terms containing x to the left, all other terms to the right
-5x=-40
x=-40/-5
x=+8
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