2x-4(x-3)=-6+4x-12

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Solution for 2x-4(x-3)=-6+4x-12 equation: 



2x-4(x-3)=-6+4x-12

We move all terms to the left:

2x-4(x-3)-(-6+4x-12)=0

We add all the numbers together, and all the variables

2x-4(x-3)-(4x-18)=0

We multiply parentheses

2x-4x-(4x-18)+12=0

We get rid of parentheses

2x-4x-4x+18+12=0

We add all the numbers together, and all the variables

-6x+30=0

We move all terms containing x to the left, all other terms to the right

-6x=-30

x=-30/-6

x=+5

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