2x-4(x-3)=-8+5x-1

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Solution for 2x-4(x-3)=-8+5x-1 equation: 



2x-4(x-3)=-8+5x-1

We move all terms to the left:

2x-4(x-3)-(-8+5x-1)=0

We add all the numbers together, and all the variables

2x-4(x-3)-(5x-9)=0

We multiply parentheses

2x-4x-(5x-9)+12=0

We get rid of parentheses

2x-4x-5x+9+12=0

We add all the numbers together, and all the variables

-7x+21=0

We move all terms containing x to the left, all other terms to the right

-7x=-21

x=-21/-7

x=+3

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