2x-4(x-3)=4+5x-19

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Solution for 2x-4(x-3)=4+5x-19 equation: 



2x-4(x-3)=4+5x-19

We move all terms to the left:

2x-4(x-3)-(4+5x-19)=0

We add all the numbers together, and all the variables

2x-4(x-3)-(5x-15)=0

We multiply parentheses

2x-4x-(5x-15)+12=0

We get rid of parentheses

2x-4x-5x+15+12=0

We add all the numbers together, and all the variables

-7x+27=0

We move all terms containing x to the left, all other terms to the right

-7x=-27

x=-27/-7

x=3+6/7

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