2x-4(x-4)=-5+2x+13

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Solution for 2x-4(x-4)=-5+2x+13 equation: 



2x-4(x-4)=-5+2x+13

We move all terms to the left:

2x-4(x-4)-(-5+2x+13)=0

We add all the numbers together, and all the variables

2x-4(x-4)-(2x+8)=0

We multiply parentheses

2x-4x-(2x+8)+16=0

We get rid of parentheses

2x-4x-2x-8+16=0

We add all the numbers together, and all the variables

-4x+8=0

We move all terms containing x to the left, all other terms to the right

-4x=-8

x=-8/-4

x=+2

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