2x-4(x-4)=-6+3x+12

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Solution for 2x-4(x-4)=-6+3x+12 equation: 



2x-4(x-4)=-6+3x+12

We move all terms to the left:

2x-4(x-4)-(-6+3x+12)=0

We add all the numbers together, and all the variables

2x-4(x-4)-(3x+6)=0

We multiply parentheses

2x-4x-(3x+6)+16=0

We get rid of parentheses

2x-4x-3x-6+16=0

We add all the numbers together, and all the variables

-5x+10=0

We move all terms containing x to the left, all other terms to the right

-5x=-10

x=-10/-5

x=+2

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