2x-4(x-4)=-6+4x+10

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Solution for 2x-4(x-4)=-6+4x+10 equation: 



2x-4(x-4)=-6+4x+10

We move all terms to the left:

2x-4(x-4)-(-6+4x+10)=0

We add all the numbers together, and all the variables

2x-4(x-4)-(4x+4)=0

We multiply parentheses

2x-4x-(4x+4)+16=0

We get rid of parentheses

2x-4x-4x-4+16=0

We add all the numbers together, and all the variables

-6x+12=0

We move all terms containing x to the left, all other terms to the right

-6x=-12

x=-12/-6

x=+2

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