2x-4(x-4)=-8+4x-12

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Solution for 2x-4(x-4)=-8+4x-12 equation: 



2x-4(x-4)=-8+4x-12

We move all terms to the left:

2x-4(x-4)-(-8+4x-12)=0

We add all the numbers together, and all the variables

2x-4(x-4)-(4x-20)=0

We multiply parentheses

2x-4x-(4x-20)+16=0

We get rid of parentheses

2x-4x-4x+20+16=0

We add all the numbers together, and all the variables

-6x+36=0

We move all terms containing x to the left, all other terms to the right

-6x=-36

x=-36/-6

x=+6

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