2x-4(x-4)=-8+5x-23

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Solution for 2x-4(x-4)=-8+5x-23 equation: 



2x-4(x-4)=-8+5x-23

We move all terms to the left:

2x-4(x-4)-(-8+5x-23)=0

We add all the numbers together, and all the variables

2x-4(x-4)-(5x-31)=0

We multiply parentheses

2x-4x-(5x-31)+16=0

We get rid of parentheses

2x-4x-5x+31+16=0

We add all the numbers together, and all the variables

-7x+47=0

We move all terms containing x to the left, all other terms to the right

-7x=-47

x=-47/-7

x=6+5/7

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