2x-4(x-4)=-8+5x-4

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Solution for 2x-4(x-4)=-8+5x-4 equation: 



2x-4(x-4)=-8+5x-4

We move all terms to the left:

2x-4(x-4)-(-8+5x-4)=0

We add all the numbers together, and all the variables

2x-4(x-4)-(5x-12)=0

We multiply parentheses

2x-4x-(5x-12)+16=0

We get rid of parentheses

2x-4x-5x+12+16=0

We add all the numbers together, and all the variables

-7x+28=0

We move all terms containing x to the left, all other terms to the right

-7x=-28

x=-28/-7

x=+4

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