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2x-4(x-4)=3x+10-5x+6
We move all terms to the left:
2x-4(x-4)-(3x+10-5x+6)=0
We add all the numbers together, and all the variables
2x-4(x-4)-(-2x+16)=0
We multiply parentheses
2x-4x-(-2x+16)+16=0
We get rid of parentheses
2x-4x+2x-16+16=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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