2x-4(x-4)=9+2x+13

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Solution for 2x-4(x-4)=9+2x+13 equation: 



2x-4(x-4)=9+2x+13

We move all terms to the left:

2x-4(x-4)-(9+2x+13)=0

We add all the numbers together, and all the variables

2x-4(x-4)-(2x+22)=0

We multiply parentheses

2x-4x-(2x+22)+16=0

We get rid of parentheses

2x-4x-2x-22+16=0

We add all the numbers together, and all the variables

-4x-6=0

We move all terms containing x to the left, all other terms to the right

-4x=6

x=6/-4

x=-1+1/2

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