2x-4(x-5)=-6+3x+16

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Solution for 2x-4(x-5)=-6+3x+16 equation:



2x-4(x-5)=-6+3x+16
We move all terms to the left:
2x-4(x-5)-(-6+3x+16)=0
We add all the numbers together, and all the variables
2x-4(x-5)-(3x+10)=0
We multiply parentheses
2x-4x-(3x+10)+20=0
We get rid of parentheses
2x-4x-3x-10+20=0
We add all the numbers together, and all the variables
-5x+10=0
We move all terms containing x to the left, all other terms to the right
-5x=-10
x=-10/-5
x=+2

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