2x-4(x-5)=-6+3x+16

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Solution for 2x-4(x-5)=-6+3x+16 equation: 



2x-4(x-5)=-6+3x+16

We move all terms to the left:

2x-4(x-5)-(-6+3x+16)=0

We add all the numbers together, and all the variables

2x-4(x-5)-(3x+10)=0

We multiply parentheses

2x-4x-(3x+10)+20=0

We get rid of parentheses

2x-4x-3x-10+20=0

We add all the numbers together, and all the variables

-5x+10=0

We move all terms containing x to the left, all other terms to the right

-5x=-10

x=-10/-5

x=+2

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