2x-4-2x=-(8x+2)x

Solution for 2x-4-2x=-(8x+2)x equation:

2x-4-2x=-(8x+2)x

We move all terms to the left:

2x-4-2x-(-(8x+2)x)=0

We add all the numbers together, and all the variables

-(-(8x+2)x)-4=0


We calculate terms in parentheses: -(-(8x+2)x), so:

-(8x+2)x

We multiply parentheses

-8x^2-2x

Back to the equation:

-(-8x^2-2x)


We get rid of parentheses

8x^2+2x-4=0

a = 8; b = 2; c = -4;
Δ = b2-4ac
Δ = 22-4·8·(-4)
Δ = 132
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{132}=\sqrt{4*33}=\sqrt{4}*\sqrt{33}=2\sqrt{33}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{33}}{2*8}=\frac{-2-2\sqrt{33}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{33}}{2*8}=\frac{-2+2\sqrt{33}}{16}
$