2x-4/5x+2=4x-8/10x+3

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Solution for 2x-4/5x+2=4x-8/10x+3 equation: 



2x-4/5x+2=4x-8/10x+3

We move all terms to the left:

2x-4/5x+2-(4x-8/10x+3)=0



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R





Domain of the equation: 10x+3)!=0

x∈R



We get rid of parentheses

2x-4/5x-4x+8/10x-3+2=0

We calculate fractions


2x-4x+(-40x)/50x^2+40x/50x^2-3+2=0

We add all the numbers together, and all the variables

-2x+(-40x)/50x^2+40x/50x^2-1=0

We multiply all the terms by the denominator


-2x*50x^2+(-40x)+40x-1*50x^2=0

We add all the numbers together, and all the variables

40x-2x*50x^2+(-40x)-1*50x^2=0

Wy multiply elements

-100x^3-50x^2+40x+(-40x)=0

We get rid of parentheses

-100x^3-50x^2+40x-40x=0

We do not support expression: x^3

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