2x-4/x+2

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Solution for 2x-4/x+2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x-(4/x)+2 = 0

2*x-4*x^-1+2 = 0

2*x^1-4*x^-1+2*x^0 = 0

(2*x^2+2*x^1-4*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^2+2*x^1-4*x^0) = 0

x^1

2*x^2+2*x-4 = 0

2*x^2+2*x-4 = 0

DELTA = 2^2-(-4*2*4)

DELTA = 36

DELTA > 0

x = (36^(1/2)-2)/(2*2) or x = (-36^(1/2)-2)/(2*2)

x = 1 or x = -2

x in { -2, 1} 

x in { -2, 1 }

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