2x-40-10x=-8(x+4)-8

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Solution for 2x-40-10x=-8(x+4)-8 equation:



2x-40-10x=-8(x+4)-8
We move all terms to the left:
2x-40-10x-(-8(x+4)-8)=0
We add all the numbers together, and all the variables
-8x-(-8(x+4)-8)-40=0
We calculate terms in parentheses: -(-8(x+4)-8), so:
-8(x+4)-8
We multiply parentheses
-8x-32-8
We add all the numbers together, and all the variables
-8x-40
Back to the equation:
-(-8x-40)
We get rid of parentheses
-8x+8x+40-40=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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