2x-40-10x=-8(x+4)-8

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Solution for 2x-40-10x=-8(x+4)-8 equation: 



2x-40-10x=-8(x+4)-8

We move all terms to the left:

2x-40-10x-(-8(x+4)-8)=0

We add all the numbers together, and all the variables

-8x-(-8(x+4)-8)-40=0



We calculate terms in parentheses: -(-8(x+4)-8), so:

-8(x+4)-8

We multiply parentheses

-8x-32-8

We add all the numbers together, and all the variables

-8x-40

Back to the equation:

-(-8x-40)



We get rid of parentheses

-8x+8x+40-40=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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