2x-40/5+2x/2=10

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Solution for 2x-40/5+2x/2=10 equation: 



2x-40/5+2x/2=10

We move all terms to the left:

2x-40/5+2x/2-(10)=0

determiningTheFunctionDomain
2x+2x/2-10-40/5=0

We add all the numbers together, and all the variables

2x+2x/2-18=0

We multiply all the terms by the denominator


2x*2+2x-18*2=0

We add all the numbers together, and all the variables

2x+2x*2-36=0

Wy multiply elements

2x+4x-36=0

We add all the numbers together, and all the variables

6x-36=0

We move all terms containing x to the left, all other terms to the right

6x=36

x=36/6

x=6

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