2x-40/5+2x/2=10

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Solution for 2x-40/5+2x/2=10 equation:



2x-40/5+2x/2=10
We move all terms to the left:
2x-40/5+2x/2-(10)=0
determiningTheFunctionDomain 2x+2x/2-10-40/5=0
We add all the numbers together, and all the variables
2x+2x/2-18=0
We multiply all the terms by the denominator
2x*2+2x-18*2=0
We add all the numbers together, and all the variables
2x+2x*2-36=0
Wy multiply elements
2x+4x-36=0
We add all the numbers together, and all the variables
6x-36=0
We move all terms containing x to the left, all other terms to the right
6x=36
x=36/6
x=6

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