2x-40=4(8-4x)

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Solution for 2x-40=4(8-4x) equation: 



2x-40=4(8-4x)

We move all terms to the left:

2x-40-(4(8-4x))=0

We add all the numbers together, and all the variables

2x-(4(-4x+8))-40=0



We calculate terms in parentheses: -(4(-4x+8)), so:

4(-4x+8)

We multiply parentheses

-16x+32

Back to the equation:

-(-16x+32)



We get rid of parentheses

2x+16x-32-40=0

We add all the numbers together, and all the variables

18x-72=0

We move all terms containing x to the left, all other terms to the right

18x=72

x=72/18

x=4

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