2x-40=8(1-x)

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Solution for 2x-40=8(1-x) equation: 



2x-40=8(1-x)

We move all terms to the left:

2x-40-(8(1-x))=0

We add all the numbers together, and all the variables

2x-(8(-1x+1))-40=0



We calculate terms in parentheses: -(8(-1x+1)), so:

8(-1x+1)

We multiply parentheses

-8x+8

Back to the equation:

-(-8x+8)



We get rid of parentheses

2x+8x-8-40=0

We add all the numbers together, and all the variables

10x-48=0

We move all terms containing x to the left, all other terms to the right

10x=48

x=48/10

x=4+4/5

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