2x-41=5(4x-1)

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Solution for 2x-41=5(4x-1) equation: 



2x-41=5(4x-1)

We move all terms to the left:

2x-41-(5(4x-1))=0



We calculate terms in parentheses: -(5(4x-1)), so:

5(4x-1)

We multiply parentheses

20x-5

Back to the equation:

-(20x-5)



We get rid of parentheses

2x-20x+5-41=0

We add all the numbers together, and all the variables

-18x-36=0

We move all terms containing x to the left, all other terms to the right

-18x=36

x=36/-18

x=-2

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