2x-4=(4x-5)/(3)

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Solution for 2x-4=(4x-5)/(3) equation: 



2x-4=(4x-5)/(3)

We move all terms to the left:

2x-4-((4x-5)/(3))=0

We multiply all the terms by the denominator


2x*3)-((4x-5)-4*3)=0

We add all the numbers together, and all the variables

2x*3)-((4x-5)=0

Wy multiply elements

6x^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{12}=0$

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