2x-4=1/2x+8

Solution for 2x-4=1/2x+8 equation:

2x-4=1/2x+8

We move all terms to the left:

2x-4-(1/2x+8)=0


Domain of the equation: 2x+8)!=0

x∈R


We get rid of parentheses

2x-1/2x-8-4=0

We multiply all the terms by the denominator


2x*2x-8*2x-4*2x-1=0

Wy multiply elements

4x^2-16x-8x-1=0

We add all the numbers together, and all the variables

4x^2-24x-1=0

a = 4; b = -24; c = -1;
Δ = b2-4ac
Δ = -242-4·4·(-1)
Δ = 592
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{592}=\sqrt{16*37}=\sqrt{16}*\sqrt{37}=4\sqrt{37}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-4\sqrt{37}}{2*4}=\frac{24-4\sqrt{37}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+4\sqrt{37}}{2*4}=\frac{24+4\sqrt{37}}{8}
$