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2x-4=2(x-6)
We move all terms to the left:
2x-4-(2(x-6))=0
We calculate terms in parentheses: -(2(x-6)), so:We get rid of parentheses
2(x-6)
We multiply parentheses
2x-12
Back to the equation:
-(2x-12)
2x-2x+12-4=0
We add all the numbers together, and all the variables
8!=0
There is no solution for this equation
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