2x-4=5(3-2x)+6

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Solution for 2x-4=5(3-2x)+6 equation: 



2x-4=5(3-2x)+6

We move all terms to the left:

2x-4-(5(3-2x)+6)=0

We add all the numbers together, and all the variables

2x-(5(-2x+3)+6)-4=0



We calculate terms in parentheses: -(5(-2x+3)+6), so:

5(-2x+3)+6

We multiply parentheses

-10x+15+6

We add all the numbers together, and all the variables

-10x+21

Back to the equation:

-(-10x+21)



We get rid of parentheses

2x+10x-21-4=0

We add all the numbers together, and all the variables

12x-25=0

We move all terms containing x to the left, all other terms to the right

12x=25

x=25/12

x=2+1/12

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