2x-4=5(3-2x)+8

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Solution for 2x-4=5(3-2x)+8 equation: 



2x-4=5(3-2x)+8

We move all terms to the left:

2x-4-(5(3-2x)+8)=0

We add all the numbers together, and all the variables

2x-(5(-2x+3)+8)-4=0



We calculate terms in parentheses: -(5(-2x+3)+8), so:

5(-2x+3)+8

We multiply parentheses

-10x+15+8

We add all the numbers together, and all the variables

-10x+23

Back to the equation:

-(-10x+23)



We get rid of parentheses

2x+10x-23-4=0

We add all the numbers together, and all the variables

12x-27=0

We move all terms containing x to the left, all other terms to the right

12x=27

x=27/12

x=2+1/4

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