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2x-4=5(x+1)-3(x+2)
We move all terms to the left:
2x-4-(5(x+1)-3(x+2))=0
We calculate terms in parentheses: -(5(x+1)-3(x+2)), so:We get rid of parentheses
5(x+1)-3(x+2)
We multiply parentheses
5x-3x+5-6
We add all the numbers together, and all the variables
2x-1
Back to the equation:
-(2x-1)
2x-2x+1-4=0
We add all the numbers together, and all the variables
-3!=0
There is no solution for this equation
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