2x-4=7(x+3)/4

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Solution for 2x-4=7(x+3)/4 equation: 



2x-4=7(x+3)/4

We move all terms to the left:

2x-4-(7(x+3)/4)=0

We multiply all the terms by the denominator


2x*4)-(7(x+3)-4*4)=0

We add all the numbers together, and all the variables

2x*4)-(7(x+3)=0

Wy multiply elements

8x^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{16}=0$

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