2x-4=8+x-5x+6(x-2)

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Solution for 2x-4=8+x-5x+6(x-2) equation: 



2x-4=8+x-5x+6(x-2)

We move all terms to the left:

2x-4-(8+x-5x+6(x-2))=0



We calculate terms in parentheses: -(8+x-5x+6(x-2)), so:

8+x-5x+6(x-2)

determiningTheFunctionDomain
x-5x+6(x-2)+8

We add all the numbers together, and all the variables

-4x+6(x-2)+8

We multiply parentheses

-4x+6x-12+8

We add all the numbers together, and all the variables

2x-4

Back to the equation:

-(2x-4)



We get rid of parentheses

2x-2x+4-4=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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