2x-4x-4=(2x-2)(x+1)

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Solution for 2x-4x-4=(2x-2)(x+1) equation:


Simplifying
2x + -4x + -4 = (2x + -2)(x + 1)

Reorder the terms:
-4 + 2x + -4x = (2x + -2)(x + 1)

Combine like terms: 2x + -4x = -2x
-4 + -2x = (2x + -2)(x + 1)

Reorder the terms:
-4 + -2x = (-2 + 2x)(x + 1)

Reorder the terms:
-4 + -2x = (-2 + 2x)(1 + x)

Multiply (-2 + 2x) * (1 + x)
-4 + -2x = (-2(1 + x) + 2x * (1 + x))
-4 + -2x = ((1 * -2 + x * -2) + 2x * (1 + x))
-4 + -2x = ((-2 + -2x) + 2x * (1 + x))
-4 + -2x = (-2 + -2x + (1 * 2x + x * 2x))
-4 + -2x = (-2 + -2x + (2x + 2x2))

Combine like terms: -2x + 2x = 0
-4 + -2x = (-2 + 0 + 2x2)
-4 + -2x = (-2 + 2x2)

Solving
-4 + -2x = -2 + 2x2

Solving for variable 'x'.

Reorder the terms:
-4 + 2 + -2x + -2x2 = -2 + 2x2 + 2 + -2x2

Combine like terms: -4 + 2 = -2
-2 + -2x + -2x2 = -2 + 2x2 + 2 + -2x2

Reorder the terms:
-2 + -2x + -2x2 = -2 + 2 + 2x2 + -2x2

Combine like terms: -2 + 2 = 0
-2 + -2x + -2x2 = 0 + 2x2 + -2x2
-2 + -2x + -2x2 = 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
-2 + -2x + -2x2 = 0

Factor out the Greatest Common Factor (GCF), '-2'.
-2(1 + x + x2) = 0

Ignore the factor -2.

Subproblem 1

Set the factor '(1 + x + x2)' equal to zero and attempt to solve: Simplifying 1 + x + x2 = 0 Solving 1 + x + x2 = 0 Begin completing the square. Move the constant term to the right: Add '-1' to each side of the equation. 1 + x + -1 + x2 = 0 + -1 Reorder the terms: 1 + -1 + x + x2 = 0 + -1 Combine like terms: 1 + -1 = 0 0 + x + x2 = 0 + -1 x + x2 = 0 + -1 Combine like terms: 0 + -1 = -1 x + x2 = -1 The x term is x. Take half its coefficient (0.5). Square it (0.25) and add it to both sides. Add '0.25' to each side of the equation. x + 0.25 + x2 = -1 + 0.25 Reorder the terms: 0.25 + x + x2 = -1 + 0.25 Combine like terms: -1 + 0.25 = -0.75 0.25 + x + x2 = -0.75 Factor a perfect square on the left side: (x + 0.5)(x + 0.5) = -0.75 Can't calculate square root of the right side. The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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