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2x-5(2x-3)=3(4x+2)
We move all terms to the left:
2x-5(2x-3)-(3(4x+2))=0
We multiply parentheses
2x-10x-(3(4x+2))+15=0
We calculate terms in parentheses: -(3(4x+2)), so:We add all the numbers together, and all the variables
3(4x+2)
We multiply parentheses
12x+6
Back to the equation:
-(12x+6)
-8x-(12x+6)+15=0
We get rid of parentheses
-8x-12x-6+15=0
We add all the numbers together, and all the variables
-20x+9=0
We move all terms containing x to the left, all other terms to the right
-20x=-9
x=-9/-20
x=9/20
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