2x-5(7-(x-6)+3x)-28=39

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Solution for 2x-5(7-(x-6)+3x)-28=39 equation: 



2x-5(7-(x-6)+3x)-28=39

We move all terms to the left:

2x-5(7-(x-6)+3x)-28-(39)=0

We add all the numbers together, and all the variables

2x-5(7-(x-6)+3x)-67=0

We move all terms containing x to the left, all other terms to the right

2x-5(7-(x-6)+3x)=67

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