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2x-5(7x-2)=-5(x-2)
We move all terms to the left:
2x-5(7x-2)-(-5(x-2))=0
We multiply parentheses
2x-35x-(-5(x-2))+10=0
We calculate terms in parentheses: -(-5(x-2)), so:We add all the numbers together, and all the variables
-5(x-2)
We multiply parentheses
-5x+10
Back to the equation:
-(-5x+10)
-33x-(-5x+10)+10=0
We get rid of parentheses
-33x+5x-10+10=0
We add all the numbers together, and all the variables
-28x=0
x=0/-28
x=0
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