2x-5(x-3)+1=2(x+3)

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Solution for 2x-5(x-3)+1=2(x+3) equation: 



2x-5(x-3)+1=2(x+3)

We move all terms to the left:

2x-5(x-3)+1-(2(x+3))=0

We multiply parentheses

2x-5x-(2(x+3))+15+1=0



We calculate terms in parentheses: -(2(x+3)), so:

2(x+3)

We multiply parentheses

2x+6

Back to the equation:

-(2x+6)



We add all the numbers together, and all the variables

-3x-(2x+6)+16=0

We get rid of parentheses

-3x-2x-6+16=0

We add all the numbers together, and all the variables

-5x+10=0

We move all terms containing x to the left, all other terms to the right

-5x=-10

x=-10/-5

x=+2

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