2x-5(x-3)=10(x-4)

Solution for 2x-5(x-3)=10(x-4) equation:

2x-5(x-3)=10(x-4)

We move all terms to the left:

2x-5(x-3)-(10(x-4))=0

We multiply parentheses

2x-5x-(10(x-4))+15=0


We calculate terms in parentheses: -(10(x-4)), so:

10(x-4)

We multiply parentheses

10x-40

Back to the equation:

-(10x-40)


We add all the numbers together, and all the variables

-3x-(10x-40)+15=0

We get rid of parentheses

-3x-10x+40+15=0

We add all the numbers together, and all the variables

-13x+55=0

We move all terms containing x to the left, all other terms to the right

-13x=-55

x=-55/-13

x=4+3/13