2x-5(x-3)=2(x-10)*

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Solution for 2x-5(x-3)=2(x-10)* equation: 



2x-5(x-3)=2(x-10)*

We move all terms to the left:

2x-5(x-3)-(2(x-10)*)=0

We multiply parentheses

2x-5x-(2(x-10)*)+15=0



We calculate terms in parentheses: -(2(x-10)*), so:

2(x-10)*

We multiply parentheses

2x-20

Back to the equation:

-(2x-20)



We add all the numbers together, and all the variables

-3x-(2x-20)+15=0

We get rid of parentheses

-3x-2x+20+15=0

We add all the numbers together, and all the variables

-5x+35=0

We move all terms containing x to the left, all other terms to the right

-5x=-35

x=-35/-5

x=+7

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