2x-5(x-3)=8(x-8)+2

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Solution for 2x-5(x-3)=8(x-8)+2 equation: 



2x-5(x-3)=8(x-8)+2

We move all terms to the left:

2x-5(x-3)-(8(x-8)+2)=0

We multiply parentheses

2x-5x-(8(x-8)+2)+15=0



We calculate terms in parentheses: -(8(x-8)+2), so:

8(x-8)+2

We multiply parentheses

8x-64+2

We add all the numbers together, and all the variables

8x-62

Back to the equation:

-(8x-62)



We add all the numbers together, and all the variables

-3x-(8x-62)+15=0

We get rid of parentheses

-3x-8x+62+15=0

We add all the numbers together, and all the variables

-11x+77=0

We move all terms containing x to the left, all other terms to the right

-11x=-77

x=-77/-11

x=+7

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